### Discussion :: Concrete Technology - Section 4 (Q.No.22)

Kenmen said: (Jul 16, 2015) | |

We know, surface area and height of pile required for storing of 1 bag of cement are 0.3 sq. m. and 0.18 m respectively. Therefore, maximum nos of bags can be stored into the given stored house = (5.4 x 2.7)/(0.3 x 0.18) = 2700 bags. |

Sivareddy said: (Mar 13, 2016) | |

How did you change 54 sq meters in 5.4? Please explain about it. |

Darshan H A said: (Jul 5, 2016) | |

Surface area and height of pile required for storing of 1 bag of cement is 0.3 sq M and 0.18 m. Therefore maximum number of bags can be stored into the given house = (54 x 2.7) / (0.3 x 0.18) = 2700 bags. |

Vivek Bhardwaj said: (Feb 28, 2017) | |

One bag of cement occupy 0.034cum vol. Why you take 0.054? |

Anurag Garg said: (Dec 26, 2017) | |

But as per rules, it is necessary to keep min 30 cm distance between the wall and first column of cement to avoid moisture. |

Chris said: (Feb 3, 2018) | |

Effective plan area is given. Already 30cm excluded. |

Ravneet said: (Sep 30, 2018) | |

The total volume of room 54 * 2.7. The volume of 1 cement bag .0347. The Number of cement bags = 54 * 2.7/.0347 = 4200. |

Jas said: (Oct 13, 2018) | |

It's the volume of cement bag not of cement; Height of bag - 0.18m (or) 18 cm. And area - 0.3sqm (or) 3000 sq cm. So the volume of bag = 0.18 * 0.3 = 0.054 cum, Volume of room - 54 * 2.7= 145.8 cum. No of bags= volume of room (warehouse)/volume of one cement bag. = 54 * 2.7/(0.18 * 0.3), =145.8/0.054, = 2700. |

Deepu Maurya said: (Oct 21, 2018) | |

54 * 2.7 ÷ (.054) = 2700. |

Sami said: (Feb 14, 2019) | |

How to find the height and area bag? |

Sikindra Yadav said: (Feb 16, 2019) | |

Yeah, you are right, agree @Darshan H A. |

Rahul Swarnkar said: (Sep 7, 2019) | |

54*2.7/.18*.3 = 2700 bags. |

Yash said: (Nov 19, 2019) | |

When you take 1 bag of cement and plan on group its cover 3000 sq cm area. And bag height is 18 cm. That by they use .3 Sqm and .18m here For a bag. |

Beewaek Mandal said: (Jan 8, 2020) | |

Simply, No. Of bags = Effective area* Max.ht of piles/ Area coverd by one bag cement is 0.3 sq.m & ht= 0.18. No= 54*2.7/0.3*0.18 = 2700 bags you must get. |

Er. Anshu Kumar said: (Jun 19, 2020) | |

Here, In first case: (standard): Area required for 1 bag of cement = 0.3 sq.m, Height of pile required for 1 bag = 0.18 m, Volume of 1 bag = 0.3 * 0.18, = 0.054 cubic metre. In second case:(Given): Plan area of warehouse = 54 sq.m, Max.height of piles = 270 cm =2.7 m, Volume of warehouse = 54*2.7. = 145.8 cubic metre. We know that; No.of bags = volume of warehouse/volume of 1 bag of cement. = 145.8/0.054. = 2700 bags.(Answer). |

Chandan Nandi said: (Aug 6, 2020) | |

2.7 How come? Please explain. |

Longti said: (Nov 27, 2020) | |

270cm = 2.7m. |

Sk Pratap said: (Feb 21, 2021) | |

As per rule the distance between two piles is 1.6m and distance from wall is 30cm and 20cm above the ground level is not included in this calculation why? According to rule, it is a bad way to store cement in ware house. |

Jahangir Abbas Sahil said: (Aug 21, 2021) | |

The total volume of room = 54 * 2.7 = 145.8 cu.m. The volume of 1 cement bag = 0.0347 (This is the wet Volume and We've to calculate at site in dry Volume). Dry Volume= Wet Vol * 1.54 to 1.57, Dry Volume= 0.0347 * 1.5, Dry Vol= 0.053 cu.m. The Number of cement bags = 145.5cum/0.053 = 2745. Hence, 2745 is near to 2700. |

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