The help for @isowyear says
which I must confess I don't understand. I thought I'd try it out and try to understand it from its output, but I can't work out what's going on here (note that my date format is set to DD/MM/YY):
d:\>ver /r
TCC 15.00.23 x64 Windows 7 [Version 6.1.7601]
TCC Build 23 Windows 7 Build 7601 Service Pack 1
d:\>echo %@isowyear[01/02/03]
2001
d:\>echo %@isowyear[01/02/06]
2001
d:\>echo %@isowyear[12/12/01]
2012
d:\>echo %@isowyear[11/11/24]
2011
d:\>echo %@isowyear[12/01/01]
2011
Can anyone clarify what the function does?
Thanks
Dan
Returns the ISO8601 numeric week date year.
which I must confess I don't understand. I thought I'd try it out and try to understand it from its output, but I can't work out what's going on here (note that my date format is set to DD/MM/YY):
d:\>ver /r
TCC 15.00.23 x64 Windows 7 [Version 6.1.7601]
TCC Build 23 Windows 7 Build 7601 Service Pack 1
d:\>echo %@isowyear[01/02/03]
2001
d:\>echo %@isowyear[01/02/06]
2001
d:\>echo %@isowyear[12/12/01]
2012
d:\>echo %@isowyear[11/11/24]
2011
d:\>echo %@isowyear[12/01/01]
2011
Can anyone clarify what the function does?
Thanks
Dan